Q.

If θ lies in the first quadrant and 5tanθ=4, then 5sinθ−3cosθsinθ+2cosθ=

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a

5/14

b

3/14

c

1/14

d

0

answer is A.

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Detailed Solution

Divide the Nr. and Dr. with cosθ, then5tanθ−3tanθ+2=4-345+2=514
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