Q.
If θ lies in the first quadrant and 5tanθ=4, then 5sinθ−3cosθsinθ+2cosθ=
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a
5/14
b
3/14
c
1/14
d
0
answer is A.
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Detailed Solution
Divide the Nr. and Dr. with cosθ, then5tanθ−3tanθ+2=4-345+2=514
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