Q.

If θ lies in the first quadrant and 5 tanθ=4 then 5sinθ−3cosθsinθ+2cosθ=

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a

514

b

314

c

114

d

0

answer is A.

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Detailed Solution

tanθ=45 ∴5tanθ−3tanθ+2=5(45)−345+2 = 514
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If θ lies in the first quadrant and 5 tanθ=4 then 5sinθ−3cosθsinθ+2cosθ=