Q.

If A lies in the second quadrant and 3tanA+4=0, then the value of 2cotA−5cosA+sinA is equal to

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a

−5310

b

2310

c

3710

d

710

answer is B.

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Detailed Solution

Using right angled triangle, we havetanA=-43⇒cotA=-34, cosA=-35 and sinA=45 ∴2cotA−5cosA+sinA=-32+3+45=2310
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