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Q.

If  limx→0 fxsin2x=8,   limx→0  gx2cosx-xex+x3+x-2=λ  and  limx→0 1+2fx1gx=1e,  thenThe value of λ islimx→0 1+fx12gx is equal to

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a

2

b

4

c

8

d

16

e

e-14

f

e-12

g

e-2

h

e-4

answer is , .

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Detailed Solution

limx→0 fxsin2x=8⇒ limx→0 fxx2sin2xx2=8⇒  limx→0 fxx2=8                                                        ...1Also,  limx→0 gx2cosx-xex+x3+x-2=λ⇒ limx→0 gxx2-21-cosxx2-ex-1x+x=λ⇒ limx→0 gxx2-4sin2x2x2-1+0=λ⇒ limx→0 gxx2=-2λ                                 ... 2Now,  limx→0  1+2fx1gx    one  power  infinity  form=            elimx→0 2fxgx=e  limx→0  2fx/x2gx/x2                         =  elimx→0  16-2λ                         =e-8λ                        = e-1  given∴   λ=8       limx→0  1+fx12gx=elimx→0  fx2gx         =elimx→0  fx/x22gx/x2        =elimx→0  82×-16        =e-14    limx→0 fxsin2x=8⇒ limx→0 fxx2sin2xx2=8⇒  limx→0 fxx2=8                                                        ...1Also,  limx→0 gx2cosx-xex+x3+x-2=λ⇒ limx→0 gxx2-21-cosxx2-ex-1x+x=λ⇒ limx→0 gxx2-4sin2x2x2-1+0⇒ limx→0 gxx2=-2λ                                 ... 2Now,  limx→0  1+2fx1gx    one  power  infinity  form=            elimx→0 2fxgx=e  limx→0  2fx/x2gx/x2                         =  elimx→0  16-2λ                         =e-8λ                        = e-1  given∴   λ=8       limx→0  1+fx12gx=elimx→0  fx2gx         =elimx→0  fx/x22gx/x2        =elimx→0  82×-16        =e-14
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If  limx→0 fxsin2x=8,   limx→0  gx2cosx-xex+x3+x-2=λ  and  limx→0 1+2fx1gx=1e,  thenThe value of λ islimx→0 1+fx12gx is equal to