If limx→0 (4x−1)13+a+bxx=13 , then the value of |ab|
we have limx→0 −(1−4x)13+a+bxx=13⇒limx→0 −1−43x+a+bxx=13⇒limx→0 (a−1)+43+bxx=13For limit to exist, a - 1 = 0 or a = 1⇒limx→0 43+bxx=13⇒43+b=13⇒b=−1