If limx→0(x−3sin3x+ax−2+b) exists and is equal to zero, then the value of a + 2b =
3
4
0
6
limx→0 sin3x+ax+bx3x3 00form by l'Hospital rule limx→03cos3x+a+3bx23x2Dr. tends to 0, Nr. tends to 0 3+a=0⇒a=-3 limx→0-9sin3x+6bx6x=-92+b=0⇒b=92