Q.
If limx→λ 2−λxλtanπx2λ=1e then λ is equal to
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a
-π
b
π
c
π2
d
-2π
answer is C.
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Detailed Solution
If limx→λ 2−λxλtanπx2λ=1e =limx→λ 2−λxλtanπx2π=elimx→λ λtanπx2π2−λx−1=elimx→λ λtanπx2λ1−λx=elimx→λ λ1−λxcotπx2π=elimx→λ λ2/x2−cosec2πx2π⋅π2λ=elimx→λ λ2x2(−1)sin2πx2λπ2λ=elimx→λ −λ2sin2πx2λ2πππ2λ2x2=e limx→λ −2λπsin2πx2λπx2λ2=e−2λπ=e−1⇒−λ⋅2π=−1∴ λ=π2
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