If limx→∞ 1+λx+μx22x=e2 then
λ=1,μ=2
λ=2,μ=1
λ=1,μ= any real constant
λ=μ=1
Given limit is
⇒elimx→∞1+λx+μx2−12x=e2⇒e2limx→∞ λ+μx=e2⇒e2λ=e2⇒λ=1,μ∈R