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Q.

If a line segment AM=a  moves in the plane XOY remaining parallel to OX so that the left end point A slides along the circle x2+y2=a2,  the locus of M is

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a

x2+y2=4a2

b

x2+y2=2ax

c

x2+y2=2ay

d

x2+y2−2ax−2ay=0

answer is B.

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Detailed Solution

A(x1−a,y1)  lies on x2+y2=a2 ⇒(x1−a)2+y12=a2locus is x2+y2−2ax=0
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