If a line segment AM=a moves in the plane XOY remaining parallel to OX so that the left end point A slides along the circle x2+y2=a2, the locus of M is
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a
x2+y2=4a2
b
x2+y2=2ax
c
x2+y2=2ay
d
x2+y2−2ax−2ay=0
answer is B.
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Detailed Solution
A(x1−a,y1) lies on x2+y2=a2 ⇒(x1−a)2+y12=a2locus is x2+y2−2ax=0