If a line segment AM=a moves in the plane XOY remaining parallel to OX so that the left end point A slides along the circle x2+y2=a2, the locus of M is

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x2+y2=4a2

x2+y2=2ax

x2+y2=2ay

x2+y2−2ax−2ay=0

answer is B.

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Detailed Solution

A(x1−a,y1) lies on x2+y2=a2 ⇒(x1−a)2+y12=a2locus is x2+y2−2ax=0

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