If the line x=a+m, y=−2 and y=mx are concurrent , then least value of a is
0
2
22
By eliminating x,y from three equations we get –2 = m (a + m) ⇒m2+am+2=0 Since m∈R⇒dis≥0
∴a2−8≥0⇒|a|≥22