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If the line x=a+my=2 and y=mx are concurrent , then least value of a is

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a
0
b
2
c
22
d
2

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detailed solution

Correct option is C

By eliminating x,y from three equations we get –2 = m (a + m) ⇒m2+am+2=0  Since m∈R⇒dis≥0∴a2−8≥0⇒|a|≥22

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