Q.
If the line y=mx+c is a common tangent to the hyperbola x2100−y264=1 and the circle x2+y2=36, then which one of the following is true?
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a
4c2=369
b
5m= 4
c
c2=369
d
8m+5 = 0
answer is A.
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Detailed Solution
If y = mx + c is a tangent to x2102−y282=1, then∴ c2=100m2−64 …(i)y=mx+c is also tangent for x2+y2=36 ,then c2=361+m2→iiFrom (i) and (ii), we obtain 100m2−64=361+m2⇒64m2=100⇒m=±54∴ c2=361+2516=3694 Putting m=±54 in (ii) ⇒4c2=369
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