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Q.

If the line y=3x cuts the curve x3+y3+3xy+5x2+3y2+4x+5y−1=0 at the points A,B,C, then OA.OB.OC is

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a

413(33−1)

b

33+1

c

23+7

d

413(33+1)

answer is A.

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Detailed Solution

Tanθ=3⇒θ=600Any point on the line is (x1+rcosθ,y1+rsinθ)=r2,3r2where r is distance from origin substituting in the curve r31+338+r2(....)+r(.......)−1=0this is cubic equation in ‘r’∴OA.OB.OC=r1r2r3=11+338=413(33−1)
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