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If the lines $x + 2 a y + a = 0, x + 3 b y + b = 0$ and $x + 4 c y + c = 0$ are concurrent, then $a, b, c$ are in

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A.P.

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Correct option is C

Since the given lines are concurrent12aa13bb14cc=0⇒−bc+2ac−ab=0⇒ b=2aca+c ⇒ a,b,c are in H.P.

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If the lines x + 2ay + a = 0, x + 3by + b = 0 and x + 4cy + c = 0 are concurrent, then a, b, c are in

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If the lines $x + 2 a y + a = 0, x + 3 b y + b = 0$ and $x + 4 c y + c = 0$ are concurrent, then $a, b, c$ are in