If the lines 3x–y+1=0 and x–2y+3=0 are equally inclined to the line y = mx, then the value of m is given by
2m2-7m-7=0
7m2-7m-7=0
7m2-2m-7=0
2m2-7m-2=0
It θ is the angle between the lines then tanθ=m−31+3m=m−(1/2)1+m(1/2)⇒ (m−3)(2+m)=±(2m−1)(3m+1)⇒ m2−m−6=±6m2−m−1⇒ 7m2−2m−7=0 or m2+1=0