Questions
If the lines and
lie along diameters of a circle of circumference then the equation of the circle is
a
x2+y2+2x−2y−23=0
b
x2+y2−2x−2y−23=0
c
x2+y2+2x+2y−23=0
d
x2+y2−2x+2y−23=0
detailed solution
Correct option is D
Lines 2x+3y+1=0 and 3x−y−4=0 intersect at (1, -1). So, the coordinates of the centre of the circle are(1, -1). Let r be the radius of the circle. Then,Circumference =10π⇒2πr=10π⇒r=5Hence, the equation of the circle is(x−1)2+(y+1)2=52 or, x2+y2−2x+2y−23=0Talk to our academic expert!
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