If the lines 2x+3y+1=0 and 3x−y−4=0lie along diameters of a circle of circumference 10π, then the equation of the circle is

Lines 2x+3y+1=0 and 3x−y−4=0  intersect at (1, -1). So, the coordinates of the centre of the circle are(1, -1). Let r be the radius of the circle. Then,Circumference =10π⇒2πr=10π⇒r=5Hence, the equation of the circle is(x−1)2+(y+1)2=52 or, x2+y2−2x+2y−23=0