Questions
If the lines and are diameters of a circle of area square units, the equation of the circle, is
a
x2+y2+2x−2y−62=0
b
x2+y2−2x+2y−62=0
c
x2+y2−2x+2y−47=0
d
x2+y2+2x−2y−47=0
detailed solution
Correct option is C
The centre of the circle is the point of intersection of its diameters 3x−4y−7=0 and 2x−3y−5=0 So, its coordinates are (1 -1). Let r be the radius of the circle. Then πr2=49π⇒r=7Hence, the equation of the circle is (x−1)2+(y+1)2=72or ,x2+y2−2x−2y−47=0Talk to our academic expert!
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