Q.

If the lines 2x + 3y + 1 = 0, 6x + 4y + 1 = 0 intersect the co-ordinate axes in 4 points, then the circle passing through the points is

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a

12x2+12y2+8x+7y+1=0

b

6x2+6y2+3x+y=0

c

12x2+12y2+8x+7y+3=0

d

x2+y2+4x−y+3=0

answer is A.

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Detailed Solution

When a circle passing through the 4 points where the lines intersecting on the axes, the points are called concyclic points. Then the equation of the circle is  L1L2 -xy term Given lines are 2x+3y+1=0,........(1)   6x+4y+1=0........(2) The equation of the circle is (1)(2)−xy     term=0(2x+3y+1)(6x+4y+1)−26xy=0⇒12x2+12y2+8x+7y+1=0
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