If the lines x−$$21=y$$−$$31=z$$−$$4$$−k and x−$$1k=y$$−$$42=z$$−$$51$$ are coplanar then k can have

Correct option is 3exactly two values

Questions

If the lines $\frac{x - 2}{1} = \frac{y - 3}{1} = \frac{z - 4}{- k}$ and $\frac{x - 1}{k} = \frac{y - 4}{2} = \frac{z - 5}{1}$ are coplanar then k can have

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detailed solution

Correct option is C

1−1−111−kk21=0⇒k2+3k=0,k=0,−3

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If the lines x−21=y−31=z−4−k and x−1k=y−42=z−51 are coplanar then k can have

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Ready to Test Your Skills?

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If the lines $\frac{x - 2}{1} = \frac{y - 3}{1} = \frac{z - 4}{- k}$ and $\frac{x - 1}{k} = \frac{y - 4}{2} = \frac{z - 5}{1}$ are coplanar then k can have