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If the lines $\frac{x - 1}{2} = \frac{y + 1}{3} = \frac{z - 1}{4}$ and $\frac{x - 3}{1} = \frac{y - k}{2} = \frac{z}{1}$ intersect then k =

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Correct option is C

Lines are intersecting x2−x1y2−y1z2−z1a1b1c1a2b2c2=0−2−1−k1234121=0⇒k=92

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If the lines x−12=y+13=z−14 and x−31=y−k2=z1 intersect then k =

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If the lines $\frac{x - 1}{2} = \frac{y + 1}{3} = \frac{z - 1}{4}$ and $\frac{x - 3}{1} = \frac{y - k}{2} = \frac{z}{1}$ intersect then k =