If the lines x−12=y+13=z−14 and x−31=y−k2=z1 intersect, then the value of k is
x−12=y+13=z−14=λ⇒ x=2λ+1,y=3λ−1 and z=4λ+1 x−31=y−k2=z1=μ⇒ x=3+μ,y=k+2μ and z=μ
Since the above lines intersect,
2λ+1=3+μ-----i3λ−1=2μ+k----iiμ=4λ+1----iii
Solving (i) and (iii) and putting the value of λand μ in (ii), k=92