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If the lines x=az+by=cz+dx=a1z+b1y=c1z+d1  are perpendicular then

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a
aa1+cc1+1=0
b
aa1+cc1−1=0
c
aa1+bb1+1=0
d
aa1+dd1−1=0

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detailed solution

Correct option is A

x−ba=y−dc=z1, x−b1a1=y−d1c1=z1 both are perpendicular

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