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Q.

If the lines x=az+b, y=cz+d; x=a1z+b1, y=c1z+d1  are perpendicular then

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a

aa1+cc1+1=0

b

aa1+cc1−1=0

c

aa1+bb1+1=0

d

aa1+dd1−1=0

answer is A.

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Detailed Solution

x−ba=y−dc=z1, x−b1a1=y−d1c1=z1 both are perpendicular
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