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If the lines $x = a z + b$ , $y = c z + d$ ; $x = a_{1} z + b_{1}$ , $y = c_{1} z + d_{1}$ are perpendicular then

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aa1+cc1+1=0

aa1+cc1−1=0

aa1+bb1+1=0

aa1+dd1−1=0

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Correct option is A

x−ba=y−dc=z1, x−b1a1=y−d1c1=z1 both are perpendicular

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If the lines x=az+b, y=cz+d; x=a1z+b1, y=c1z+d1 are perpendicular then

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If the lines $x = a z + b$ , $y = c z + d$ ; $x = a_{1} z + b_{1}$ , $y = c_{1} z + d_{1}$ are perpendicular then