If the lines y=(2+3)x+4 and y=kx+6 are inclined  at an angle 60∘ to each other, then the value of k will be

y=(2+3)x+4----(1)y=kx+6-----(2)By⁡(1)⇒m1=(2+3)By⁡(2)⇒m2=k∴ tan⁡60∘=m1−m21+m1m2                  3=2+3-k1+k2+3⇒3+23k+3k=2+3-k⇒23+4k=2⇒k=2-3