If loga⁡b=2,logb⁡c=2, and log3⁡c=3+log3⁡a then the value of c/(ab) is

log3⁡c=3+log3⁡a or  log3⁡ca=3 or c=27a-----i loga⁡b=2;logb⁡c=2⇒ loga⁡b⋅logb⁡c=4⇒ loga⁡c=4⇒ c=a4From Eqs. (i) and (ii), we get a = 3, c = 81. From loga b=2,we have b =a2 =9. Hence, c/(ab) = 3.