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$If \log_{2} (a + b) + \log_{2} (c + d) \geq 4, where a, b, c are positive numbers. Then the$ $minimum value of expression a + b + c + d is$

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Correct option is C

(a+b)(c+d)≥16 ∵AM≥GM, we have (a+b)+(c+d)2≥(a+b)(c+d)≥4 ⇒a+b+c+d≥8

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If log2⁡(a+b)+log2⁡(c+d)≥4, where a,b,c are positive numbers. Then the minimum value of expression a+b+c+d is

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$If \log_{2} (a + b) + \log_{2} (c + d) \geq 4, where a, b, c are positive numbers. Then the$ $minimum value of expression a + b + c + d is$