If log2(a+b)+log2(c+d)≥4, where a,b,c are positive numbers. Then the minimum value of expression a+b+c+d is
2
4
8
16
(a+b)(c+d)≥16 ∵AM≥GM, we have
(a+b)+(c+d)2≥(a+b)(c+d)≥4 ⇒a+b+c+d≥8