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Questions  

If loge(a+b2)=12logea+logeb, then relation between a and b will be

a
a=b
b
a=b2
c
2a=b
d
a=b3

detailed solution

Correct option is A

loge(a+b2)=12(logea+logeb)=12loge(ab)=logeab⇒a+b2=ab⇒a+b=2ab⇒a-b2=0⇒a-b=0⇒a=b.

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