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If loge(a+b2)=12logea+logeb, then relation between a and b will be

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a

a=b

b

a=b2

c

2a=b

d

a=b3

answer is A.

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Detailed Solution

loge(a+b2)=12(logea+logeb)=12loge(ab)=logeab⇒a+b2=ab⇒a+b=2ab⇒a-b2=0⇒a-b=0⇒a=b.

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