Q.
If logkx⋅log5k=logx5,k≠1,k>0 then x is equal to
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a
k
b
1/5
c
5
d
none of these
answer is B.
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Detailed Solution
logkx⋅log5k=logx5 or logxlogklogklog5=logx5 or logxlog5=logx5 or log5x=1log5x or log5x2=1 or log5x=±1⇒ x=5±1⇒ x=15,5
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