If logkx⋅log5k=logx5,k≠1,k>0 then x is equal to
k
1/5
5
none of these
logkx⋅log5k=logx5 or logxlogklogklog5=logx5 or logxlog5=logx5 or log5x=1log5x or log5x2=1 or log5x=±1⇒ x=5±1⇒ x=15,5