If log102=a,log103=b then log0.72(9.6) in terms of a and b is equal to
2a+3b−15a+b−2
5a+b−13a+2b−2
3a+b−22a+3b−1
2a+5b−23a+b−1
log0.72(9.6)=log721009610=log1096−log1010log1072−log10100=log1025×3−1log1023×32−2=5a+b−13a+2b−2