Q.

If log4⁡5=a and log5⁡6=b, then log3⁡2 is equal to

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a

12a+1

b

12b+1

c

2ab+1

d

12ab-1

answer is D.

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Detailed Solution

Here. 5=4a and 6=5b.  Let log3⁡2=x, then 2=3x. now  6=5b=4ab=4ab∴ 2=22ab−1x=2x(2ab−1)⇒ x(2ab−1)=1
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