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If $\log_{4} 5 = a and \log_{5} 6 = b,$ then $\log_{2} 3$ is equal to

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12a+1

12b+1

2ab+1

12ab-1

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detailed solution

Correct option is D

ab=log45.log56=log46=12log26ab=121+log23⇒2ab-1=log23∴log32=12ab-1.

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If log45=a and log56=b, then log23 is equal to

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If $\log_{4} 5 = a and \log_{5} 6 = b,$ then $\log_{2} 3$ is equal to