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Q.

If log10⁡2,log10⁡2x+1 and  log10⁡2x+3 are in A.P., then

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a

x = 0

b

x = 1

c

x=12log10⁡2

d

x=12log2⁡5

answer is D.

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Detailed Solution

2,2x+1,2x+3 are in G.P.⇒2x+12=22x+3⇒22x=5⇒x=12log2⁡5
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