If log52,log52x−5 and log52x−7/2 are in A.P., then x is equal to
7
3
4
8
As log52,log52x−5, log52x−7/2 are in A.P., we get 2log52x−5=log52+log52x−7/2⇒ 2x−52=22x−7/2⇒ 2x2−122x+32=0 ⇒ 2x−42x−8=0⇒ 2x=22,23 ⇒ x=2,3.Clearly, x≠2. Therefore x=3