If log3⁡5+4log3⁡(x−1)=2,then x is equal to

We must have x-1>0 ⇒ x>1----iand  5+4log3⁡(x−1)>0or  4log3⁡(x−1)>−5or  log3⁡(x−1)>−54or  x−1>3−5/4or  x>1+3−5/4----iiFrom Eqs. (i) and (ii), we get  x>1+3−5/4∴ 5+4log3⁡(x−1)=9⇒ 4log3⁡(x−1)=4 or  log3⁡(x−1)=1 or  x−1=3 or x=4