If ${\log }_{|\sin \mathrm{x}|}|\cos \mathrm{x}|+{\log }_{|\cos \mathrm{x}|}|\sin \mathrm{x}|=2,\text{ then }|\tan \mathrm{x}|$ is equal to____.

$\begin{array}{l}\text{ Here, }{\log }_{|\sin \mathrm{x}|}|\cos \mathrm{x}|+\frac{1}{{\log }_{|\sin \mathrm{x}|}|\cos \mathrm{x}|}=2\\ \Rightarrow \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\mathrm{y}+\frac{1}{\mathrm{y}}=2,\text{ where }\mathrm{y}={\log }_{|\sin \mathrm{x}|}|\cos \mathrm{x}|\\ \Rightarrow \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\mathrm{y}=1\Rightarrow {\log }_{|\sin \mathrm{x}|}|\cos \mathrm{x}|=1\\ \Rightarrow \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}|\sin \mathrm{x}|=|\cos \mathrm{x}|\\ \Rightarrow \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}|\tan \mathrm{x}|=1\end{array}$