If logxb−c=logyc−a=logza−b, then which of the following is/are true?
xyz=1
xaybzc=1
xb+cyc+aza+b=1
xyz=xaybzc
Let logkxb−c=logkyc−a=logkza−b=p
⇒ x=kp(b−c),y=kp(c−a),z=kp(a−b)⇒ xyz=kp(b−c)kp(c−a)kp(a−b) =kp(b−c)+p(c−a)+p(a−b)=k0=1xaybzc=kpa(b−c)kpb(c−a)kpc(a−b)=k0=1xb+cyc+aza+b=kp(b+c)(b−c)kp(c+a)(c−a)kp(a+b)(a−b) =k0=1