First slide
Types of real valued functions XI
Question

If logxbc=logyca=logzab, then which of the following is/are true?

Moderate
Solution

Let logkxbc=logkyca=logkzab=p

 x=kp(bc),y=kp(ca),z=kp(ab) xyz=kp(bc)kp(ca)kp(ab) =kp(bc)+p(ca)+p(ab)=k0=1xaybzc=kpa(bc)kpb(ca)kpc(ab)=k0=1xb+cyc+aza+b=kp(b+c)(bc)kp(c+a)(ca)kp(a+b)(ab) =k0=1

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