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Q.

If ∫log10x dx=K.xlogf(x)+c then K,f(x)=

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a

loge10,xe

b

log10e,ex

c

log210,xe

d

log10e,xe

answer is D.

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Detailed Solution

∫logxlog10 dx =1log10[(logx)x−∫x1xdx] =1log10[xlogx−x]+c =(log10e)x[logx−loge]+c K=log10e , f(x)=(xe)

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