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If log2(5.2x+1),log4(21x+1) and 1 are in A.P, then x equals 

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a
log2⁡5
b
1-log2⁡5
c
log5⁡2
d
None of these

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detailed solution

Correct option is B

The given numbers are in A.P.   ∴2log4⁡(21−x+1)=log2⁡(5.2x+1)+1⇒2log22⁡(22x+1)=log2⁡(5.2x+1)+log2⁡2⇒22log2 (22x+1)=log2⁡(5.2x+1)2⇒log2⁡(22x+1)=log2⁡(10.2x+2)⇒22x+1=10.2x+2⇒2y+1=10y+2,where2x=y∴10y2+y−2=0⇒(5y−2)(2y+1)=0⇒y=2/5⇒2x=2/5⇒x=log2⁡(2/5)=log2⁡2−log2⁡5=1−log2⁡5


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If log2(5.2x+1),log4(21x+1)and 1 are in A.P, then x is equal to


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