If log2x+log2y≥6 then the least value of x + y is
4
8
16
32
Given log2x+log2y≥6
⇒ log2(xy)≥6⇒ xy≥64
Also to define log2x and log2y we have
x>0,y>0.
Since A.M. ≥ G.M., we have
x+y2≥xyor x+y≥2xy≥16