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Questions  

If 12log0.1x2 then

a
The maximum value of x is 1/10
b
x lies between 1/100 and 1/10
c
x does not lie between 1/100 and 1/10
d
The minimum value of x is 1/100

detailed solution

Correct option is A

12≤log0.1 x≤2 12≤log0.1 x⇒log0.10.11/2≤log0.1 x ⇒0.11/2≥x⇒x≤110 log0.1 x≤2⇒log0.1 x≤log0.1 0.12 x≥0.12⇒x≥1100, ∴1100≤x≤110. Hence, xmax=110, xmin=1100.

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