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Q.

If log10⁡12x+x−1=xlog10⁡5−1 then x=

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a

4

b

3

c

2

d

1

answer is D.

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Detailed Solution

R.H.S. =xlog10⁡5−log10⁡10=xlog10⁡510=log10⁡12x⇒12x+x−1=12xThereforex-1=0  or  x=1.
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