First slide
Arithmetic progression
Question

If logyx,logzy,15logxz are in A.P., then  

Moderate
Solution

Let d be the common difference of the A.P.

then,logyx=1+dx=y1+dlogzy=1+2dy=z1+2d

 and 15logxz=1+3dz=x(1+3d)/15 x=y1+d=z(1+2d)(1+d) =x(1+d)(1+2d)(1+3d)/15 (1+d)(1+2d)(1+3d)=15 6d3+11d2+6d+16=0 (d+2)6d2d+8=0d=2 x=y1+d=y1,y=z1+2d=z3 and x=z31=z3.

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