If a < b < c < d, then the roots of the equation (x-a)(x -c) +2(x - b)(x - d) =0 are
real and distinct
real and equal
imaginary
None of these
Given equation can be rewritten as 3x2−(a+c+2b+2d)x+ac+2bd=0∴Discriminant, D=(a+c+2b+2d)2−4⋅3(ac+2bd)={(a+2d)+(c+2b)}2−12(ac+2bd)={(a+2d)−(c+2b)}2+4(a+2d)(c+2b)−12(ac+2bd)={(a+2d)−(c+2b)}2−8ac+8ab+8dc−8bd={(a+2d)−(c+2b)}2+8(c−b)(d−a)Which is +ve, since a < b < c < d. Hence, roots are real and distinct.