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Questions  

If π<α<3π2, the the expression 4sin4α+sin22α+4cos2π4α2 is equal to

a
2+4sin⁡α
b
2−4sin⁡α
c
2
d
none of these

detailed solution

Correct option is C

We have,4sin4⁡α+sin2⁡2α+4cos2⁡π4−α2=4sin2⁡αsin2⁡α+cos2⁡α+41+cos⁡π2−α2=2|sin⁡α|+2(1+sin⁡α)=−2sin⁡α+2(1+sin⁡α)=2                      ∵ sin⁡α<0] for α∈3π/2

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