If π<α<3π2, the the expression 4sin4α+sin22α+4cos2π4−α2 is equal to
2+4sinα
2−4sinα
2
none of these
We have,
4sin4α+sin22α+4cos2π4−α2=4sin2αsin2α+cos2α+41+cosπ2−α2=2|sinα|+2(1+sinα)=−2sinα+2(1+sinα)=2 ∵ sinα<0] for α∈3π/2