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If $0 < θ < \frac{π}{2}, \tan θ = \frac{\cos 29^{0} + \sin 29^{0}}{\cos 29^{0} - \sin 29^{0}}$ then $θ =$

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Correct option is B

tanθ=cos29+sin29cos29-sin29 devide numerator and denominator with cos29 tanθ=1+tan291-tan29=tan(45+29)

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If 0<θ<π2,tanθ=cos290+sin290cos290−sin290 then θ=

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If $0 < θ < \frac{π}{2}, \tan θ = \frac{\cos 29^{0} + \sin 29^{0}}{\cos 29^{0} - \sin 29^{0}}$ then $θ =$