First slide

Trigonometric Identities

Question

If $π < α < \frac{3 π}{2}, then \sqrt{\frac{1 - \cos α}{1 + \cos α}} + \sqrt{\frac{1 + \cos α}{1 - \cos α}}$ is equal to

Easy

A

$\frac{2}{\sin α}$
B

$- \frac{2}{\sin α}$
C

$\frac{1}{\sin α}$
D

$- \frac{1}{\sin α}$

Solution

$\begin{matrix} \sqrt{\frac{1 - \cos α}{1 + \cos α}} + \sqrt{\frac{1 + \cos α}{1 - \cos α}} = \frac{1 - \cos α + 1 + \cos α}{\sqrt{1 - \cos^{2} α}} \\ = \frac{2}{| \sin α |} = \frac{2}{- \sin α} (∵ π < α < 3 π / 2) \end{matrix}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App