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If $0 < θ < π / 8,$ then $\sqrt{2 + \sqrt{2 + 2 \cos (4 θ)}}$ is equal to

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2cos⁡θ

−2cos⁡θ

2sin⁡θ

−2sin⁡θ

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detailed solution

Correct option is A

Use 1+cos⁡2A=2cos2⁡A

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If 0<θ<π/8, then 2+2+2cos⁡(4θ) is equal to

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If $0 < θ < π / 8,$ then $\sqrt{2 + \sqrt{2 + 2 \cos (4 θ)}}$ is equal to