If Lt1+ax+bx22x=e2, then the values of a and b are
a∈R,b∈R
a=1 and b=2
a∈R, b=2
a=1, b∈R
limx→∞1+ax+bx22x=e⇒expLtx→∞ax+bx22x=e2⇒e2a=e2⇒2a=2⇒a=1∴a=1 and b∈R