If 0<x<π2 and sinnx+cosnx>1 then
n∈2,∞
n∈−∞,2
n∈−1,1
None of these
Since 0<x<π2 ∴0<sinx<1 and 0<cosx<1When n=2, sinnx+cosnx=1 when n>2, bothsinnx and cosnx will decrease and hence sinnx +cosnx<1When n<2,both sinnx and cosnx will increase andhence sinnx+cosnx≥1 for n≤2Thus sinnx+cosnx≥1 for n≤2