If 0<x<π/2 and sin(2sinx)=cos(2cosx) then tanx+cotx=aπC−b where a+b+c=
32
16
50
64
sin(2sinx)= sin(π/2−2cosx)⇒ 2sinx=π/2−2cosx⇒ sinx+cosx=π/4⇒ 1+sin2x=π2/16
tanx+cotx=2sin2x=32π2−16a=32, b=16, c=2