Correct option is 1cosx>1−2xπ

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$If 0 < x < \frac{π}{2}, then$

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cosx>1−2xπ

cosx<1−2xπ

cosx>2xπ

cosecx>2xπ

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detailed solution

Correct option is A

∴cosx>1−2xπ

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If 0<x<π2, then

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$If 0 < x < \frac{π}{2}, then$