First slide

Introduction to linear inequalities

Question

$If 16 < x^{2} \leq 18 then x \in$

Very Easy

A

$[- 4, 3 \sqrt{2}]$
B

$[- 3 \sqrt{2}, 4]$
C

$[- 3 \sqrt{2}, - 4) \cup (4, 3 \sqrt{2}]$
D

None of these

Solution

$\begin{array}{l} 16 < x^{2} \leq 18 \\ \Rightarrow x \in [- 3 \sqrt{2}, - 4) \cup (4, 3 \sqrt{2}] \end{array}$

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