Correct option is 3[−32,−4)∪(4,32]

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$If 16 < x^{2} \leq 18 then x \in$

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[−4,32]

[−32,4]

[−32,−4)∪(4,32]

None of these

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detailed solution

Correct option is C

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If 16<x2≤18 then x∈

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$If 16 < x^{2} \leq 18 then x \in$